20x+1-x+5^2=-5-x^2-3x

Solution for 20x+1-x+5^2=-5-x^2-3x equation:

20x+1-x+5^2=-5-x^2-3x

We move all terms to the left:

20x+1-x+5^2-(-5-x^2-3x)=0

We add all the numbers together, and all the variables

-(-5-x^2-3x)+19x+26=0

We get rid of parentheses

x^2+3x+19x+5+26=0

We add all the numbers together, and all the variables

x^2+22x+31=0

a = 1; b = 22; c = +31;
Δ = b2-4ac
Δ = 222-4·1·31
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-6\sqrt{10}}{2*1}=\frac{-22-6\sqrt{10}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+6\sqrt{10}}{2*1}=\frac{-22+6\sqrt{10}}{2}
$